Question

replace y by a suitable digit so that 65y33 is divisible by 3​

Answer 1

Answer:

Step-by-step explanation:

>> 6 + 5 + y + 3 + 3 equal to 17 + y

>> 17 + y should be divisible by 3 for 65y33 to be divisible by 3( by 3's         divisibility rule)

>> So y can be 1 or 4 or 7 for 65y33 to be divisible by 3.

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Answer 2

65y33 is divisible by 3 then y is ?

Divisiblity rule for 3 is = sum of all digits is divided by 3

So, 6+5+y+3+3 = 17 + y

If y=1 then 17+1= 18 ( yes)
If y=2 then 17+2= 20 (no)
If y= 4 then 17+4 = 21 (yes)
If y=6 then 17+6= 23 (no)
If y=7 then 17+7= 24 (yes)

Therefore, y is 1,4,7.

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