Question

replu mannnnnnnnnnnnnnnnnnnnn or womeennnnn​

Answer 1

$\Large \bold{\underline{\underline \purple{Given:}}}$

$( \frac{11}{9}) ^3 \times (\frac{9}{11})^6 = (\frac{11}{9} )^{2x-3}$

$\Large{\bold{\underline{\underline{\pink{\bf{Req}\green{uir}\red{ed}\:\orange{ans}\blue{wer}}}}}}$

The value of x

$\Large \bold{\underline{\underline \blue{Solution:-}}}$

$( { \frac{11}{9} })^{3} \times ({ \frac{9}{11}) }^{6} = { \frac{11}{9} }^{2x - 3}$

$=> ({ \frac{11}{9} )}^{2} \times ({ \frac{11}{9} )}^{ - 6} = { \frac{11}{9} }^{2x - 3}$

$= > ({ \frac{11}{9} })^{3 + ( - 6)} = { \frac{11}{9} }^{2x - 3}$

$= > ({ \frac{11}{9}) }^{3 - 6} = { \frac{11}{9} }^{2x - 3}$

$= > ( { \frac{11}{9}) }^{ - 3} = { \frac{11}{9} }^{2x - 3}$

$= > - 3 = 2x - 3$

$= > 2x = 0$

$= > x = 0$

$\small\bold {Hence\:the \:value\:of\:x\:is \:0}$

$\Large \bold{\underline \red{More\:to\:know:-}}$

${a}^{m} = \frac{1}{ {a}^{ - m} }$

${a}^{m} \times {a}^{n} = {a}^{m + n}$

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$

${a}^{0} = 1$

${a}^{1} = a$