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Answer:
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Step-by-step explanation:
A number is 4 times another number,
x = 4y…Eq..1
if 21 is added to both the numbers then first number becomes 7/4 times the other number.
(x + 21)/(y + 21) = 7/4
Cross multiplication
4 (x + 21) = 7 (y + 21)
4x + 84 = 7y + 147
4x - 7y = 147 – 84
4x - 7y = 63…Eq..2
Now putting the value of x from Eq.1 to Eq..2
4 (4y) - 7y =63
16y – 7y = 63
9y = 63
y = 63/9
y = 7
One number is 7
To derive the other number, putting the value of y in Eq..1
x = 4y
x = 4 × 7
x = 28
The other number is 28
Thus the two numbers are 7 and 28 .Now Checking the correctness of answer by substituting the values of both numbers in the Eq..2
4x - 7y = 63
4 × 28 - 7 × 7 = 63
112 - 49 = 63
63 = 63
Means answer is correct.
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Answer:
28, 7
Step-by-step explanation:
let the no be x
so, 4x-x=21
3x=21
x=21/3
x=7
1 number-7
2 number-7*4=28