Question

represent 0.8 + 0.7 bar + 0.43 bar in p/q

Answer 1

Answer:

Step-by-step explanation:

Answers

0.8 bar we can represent like this

0.8+0.08+0.008+0.0008..........

So, it is in G.P

So,

a = 0.8

r = T2/T1 = 0.08/0.8 = 0.1

S(infinity) = ?

S(infinity) = a/(1-r)

S(infinity) = 0.8/(1-0.1)

S(infinity) = 0.8/0.9

S(infinity) = 8/10/9/10

S(infinity) = 8/10×10/9

S(infinity) = 8/9

0.7 bar we can represent like this

0.7+0.07+0.007+0.0007

So, it is in G.P

So,

a = 0.7

r = 0.1

S(infinity) = ?

S(infinity) = a/(1-r)

S(infinity) = 0.7/(1-0.1)

S(infinity) = 7/10/9/10

S(infinity) = 7/10×10/9

S(infinity) = 7/9

0.43 bar we can represent like this

0.43+0.0043+0.000043.................

So, it is in G.P

So,

a = 0.43

r = 0.01

S(infinity) = ?

S(infinity) = a/(1-r)

S(infinity) = 0.43/(1-0.01)

S(infinity) = 43/100/99/100

S(infinity) = 43/100×100/99

S(infinity) = 43/99

So,

0.8 bar + 0.7 bar + 0.43 bar

= 8/9+7/9+43/99

= (8+7)/9+43/99

= 15/9+43/99

= (15×11)/99

= 165/99

So, your answer is 165/99.