Question

represent (1 + √9.5) on the number line

Answer 1

Step 1:

Root(9.5) = root(9+ 0.5) 9 is 3 squared. Make the base length AB be 3 easily drawn with a ruler and then draw a line perpendicular to our number line from point B.



Now from B we have to mark point C on the dotted line which will be root(0.5) away from B.

Step 2:

Using same concept root(0.5) can be considered as the hypotenuse of a right triangle with other two sides of length 0.5.

I.e root(0.5) = root(0.25+0.25). Since a right triangle having equal lengths will be having both the remaining angles equal to 45degrees (isoceles right triangle) make a straight line inclined at 45degrees from point B and mark a point D at a distance of 0.5 from B on it.



Step 3:

From the point D mark a line perpendicular to the new dotted line joining the original dotted line as shown. The point so obtained will be C which is root(0.5) away from B.



Step 4:

Join BC which will be equal to root (0.5) in length exactly. Also join points AC and here we go. Cheers AC= root(9.5).



Step 5: The final step take a compass using A as centre make an arc cutting our number line at O.



Cheers AO is equal to root(9.5)! Now extend line segment from A behind by 1 unit to make final length equal to 1+root(9.5) as required!

Step 6:

So length PO will be 1+root(9.5).

Thank you

Answer 2

cant understant please give proper ans.