Represent 49 using 2,3,5 ?(use only sum and multiplication and twice a number only and the number given to you is 1 as initial number
Answers
49 = (1 + 3 + 3) × (2 + 5)
Step-by-step explanation:
We have to express 49 with algebraic operations - sum and multiplication among the numbers 2, 3 and 5, also taking 1 as the initial number in the expression.
We have found,
49 = (1 + 3 + 3) × (2 + 5)
Confirmation of conditions:
• 1 as the initial number.
• Using sum and multiplication.
• One number used twice, which is 3.
Thus confirmed.
((1 + 3 )* 5 + 2 ) * 2 + 5 = 49
Step-by-step explanation:
Solution :
1 + 3 * 5 + 2 * 2 + 5 ( do not apply Bodmas here , solve in the sequence as terms come)
written with brackets for better Clarification
((1 + 3 )* 5 + 2 ) * 2 + 5 = 49
= ( 4 * 5 + 2) * 2 + 5
= (20 + 2) *2 + 5
= 22 * 2 + 5
= 44 + 5
= 49
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