Represent √5.7 on the number line
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Answered by
43
Heya,
Here is your answer:-
》 Draw 5.7cm and mark the end points as A & B
》 From B extent 1cm and mark as point C and [1] {as shown in the above pic}
》 And later extend the line and mark the numbers.
》 Draw a perpendicular bisector [90deg] From points A & C. And draw the dotted line and mark the meeting point as O
》Taking O as centre, make a semi circle starting from A and end it at point C
》 From B, Draw a 90deg line. And mark the meeting point as D
》 Taking B as centre cut an arc that touches the number line.
》 Mark the meeting point of the arc on the number line as P and that point P is the location of √5.7
Hope my answer helps you :)
Regards,
Shobana
Here is your answer:-
》 Draw 5.7cm and mark the end points as A & B
》 From B extent 1cm and mark as point C and [1] {as shown in the above pic}
》 And later extend the line and mark the numbers.
》 Draw a perpendicular bisector [90deg] From points A & C. And draw the dotted line and mark the meeting point as O
》Taking O as centre, make a semi circle starting from A and end it at point C
》 From B, Draw a 90deg line. And mark the meeting point as D
》 Taking B as centre cut an arc that touches the number line.
》 Mark the meeting point of the arc on the number line as P and that point P is the location of √5.7
Hope my answer helps you :)
Regards,
Shobana
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Narender111:
Is this your rank brainly banefactor??
Answered by
1
Answer:
here is your answer
Step-by-step explanation:
1. draw 5.7 cm and mark the end point A and B.
2. from B extend 1 cm and Mark as point c and[1]
3. an later to extend the line on mark the numbers.
4. draw a perpendicular bisector (90 degree) from point A and C . and draw the dotted line and mark the meeting point as o.
Hope you like
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