Represent √5 on the number line
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To draw square root of 5 on a number line, following steps are to be followed.
Step 1: Draw a number line. ...Step 2: Mark a point A as -5 on the number line.Step 3: Mark a point C as 1 on the number line.Step 4: Mark a point B as the mid-point of AC.Step 5: With point B as the centre and radius as AB draw a semicircle.
Step 1: Draw a number line. ...Step 2: Mark a point A as -5 on the number line.Step 3: Mark a point C as 1 on the number line.Step 4: Mark a point B as the mid-point of AC.Step 5: With point B as the centre and radius as AB draw a semicircle.
Anonymous:
can you show the picture of the number line
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Step 1 :- Draw a number line.
Step 2 :- Mark points A, B on 0 and 2 respectively.
Step 3 :- Draw BC of 1 unit perpendicular to the number line.
Step 4 :- Join AC. The length of AC should be √5 because the triangle ABC thus formed is a right triangle and AB² + BC² = AC², i. e., 2² + 1² = 4 + 1 = 5.
Step 5 :- Draw a semicircle with A as centre and AC as radius. The semicircle intersects the number line at M at left and N at right.
Here M indicates -√5 and N indicates √5.
Hope this helps. Thank you. Have a nice day.
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