Represent √5 on the number line.pls show the picture of the number line you did.
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By Pythagoras Thorum
(OA)^2= (OB)^2 + (AB)^2
(OA)^2= (2)^2 + (1)^2
(OA)^2 = 4+1
(OA)^2 = 5
(OA) = √5
Hope it helps ...
Sorry my attachment is not working hope u will be helpful by this ...
(OA)^2= (OB)^2 + (AB)^2
(OA)^2= (2)^2 + (1)^2
(OA)^2 = 4+1
(OA)^2 = 5
(OA) = √5
Hope it helps ...
Sorry my attachment is not working hope u will be helpful by this ...
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hope this helps you...
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