Represent √7 and √10. 6 on the number line
Answers
Answer:
Area = 104 cm² ✬
Step-by-step explanation:
Given:
PQST is a rhombus.
TSR is a straight line.
QRS is a right angle triangle at R.
To Find:
What's is the area of whole figure ?
Solution: Let the length of SR be x cm.
As we know that
All sides of a rhombus are equal and opposite sides are parallel.
∴ PQ = QS = ST = TP = 10 cm
∴ Height of PQST = QR = 8 cm
So each side of rhombus will be 10 cm and height will be 8 cm
★ Area of Rhombus = Base × Height ★
➟ Ar. PQST = TS × QR
➟ (10 × 8) cm²
➟ 80 cm²
Now in ∆QRS , we have
QR = 8 cm {perpendicular}
SR = Base
QS = 10 cm {hypotenuse}
Applying Pythagoras Theorem
★ Hypotenuse² = P² + B² ★
➨ 10² = 8² + x²
➨ 100 – 64 = x²
➨ √36 = x
➨ 6 = x
So length of base of ∆ is 6 cm.
★ Area of ∆ = 1/2 × Base × Height ★
➼ Area ∆QSR = 1/2 × 6 × 8
➼ (3 × 8) cm²
➼ 24 cm²
∴ Total area of figure = Area (∆ + Rhombus)
\implies{\rm }⟹ 24 + 80
\implies{\rm }⟹ 104 cm²
Hence, the area of whole diagram