Question

represent √9.3 on number line ???


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Answer 1

${\mathfrak {\purple{Answer}}}$

Steps:

1) Draw a line segment AB of length 9.3 units.

2) Extend the line by 1 unit more such that BC=1 unit .

3) Find the midpoint of AC.

4) Draw a line BD perpendicular to AB and let it intersect the semicircle at point D.

5) Draw an arc DE such that BE=BD.

Therefore, BE= √9.3 units

❥ $\mathtt{have~a ~happy~moments~ahead}$

❥${\mathtt{\purple{ Army~Borahae~♡}}}$

Answer 2

Answer:

• firstly draw a line of 9.3cm label it line AB now add 1cm more on the line now label it C
• draw a perpendicular on number line AC
• now open your compass at the radius of AO now draw a semi circle
• now draw a perpendicular from B to C and label it D
• then open your compass at the radius of BD
• now draw an arch from B to number line it will cut at the point of √9.3
• this is the required figure