Question

Represent √9.3 on number line with Pythagoras theorm.​

Answer 1

here is your answer

I hope it will help you

Answer 2

EXPLANATION:

• draw a number line of 9.3 CM and add more 5 cm.
• take 10.3 CM(9.3+1) and A as the centre and take random radius and mark at both the sides and the arcs will bisect each other.
• then draw a line through both the bisecting arcs. here this will form the midpoint of the line between 10.3 cm and point A. let the midpoint be capital M.
• take M as the centre and point A as the radius, make a semicircle.
• draw a 90 degree angle on point b and draw the line till the the circumference of the semicircle. let the point be O.
• here,OB will be root √9.3.
• taking the radius as OB, draw an Arc till the number line.
• this is the location of√9.3

hope it helps you...