Question

Represent an equation of a straight line which is parallel to x-axis and at a distance of 2.5 units below it.
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Answer 1

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Any straight line parallel to x−axis is given by y=k, where k is the distance of the line from x−axis. Here k=−3, because it is below x axis then the equation of the line is y=−3.

Answer 2

Answer:

Equation of line is $y + 2.5 =0$

Step-by-step explanation:

Straight line:

A straight line is a line with no curves extending infinitely to both sides. The general equation of a straight line is $ax + by + c=0$

or

$y=mx+c$

where $m$ is the slope of the line.

Equation of straight line parallel to x - axis:

In an x-y plane, the horizontal line is the x-axis and the vertical line in the plane is the y-axis.

We know that, a point on x-axis has the coordinates $(x,0)$ where the y-coordinate is 0. So, the equation of x-axis is given by y=0.

Therefore, the equation of a line parallel to x-axis can be written as

$y=k$

where k is a constant value or the distance from the x-axis to the line.

• If the line is above x-axis, k will be positive.
• If the line is below x-axis, k will be negative.

Given:

Straight line is parallel to x-axis and the line appears to be 2.5 units below the x-axis.

i.e., $k = -2.5$

Equation of line is given by,

$y=k\\\\= > y=-2.5\\\\= > y+2.5 =0$

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