Math, asked by dakshsharma75, 1 year ago

represent geometrically √8.1 on number line

Answers

Answered by RajshreeDiya
137
Draw a line 8.1
then draw 1cm extra which makes it 9.1
mark A, B at 8.1 and C at 9.1
take a compass and from point C , take more than half draw perpendicular bisector.
From point O, draw a arch from A to C.
construct 90° at point B.
and from point B drop the arch.

Hope this helps!!

Attachments:
Answered by amitnrw
20

Given : root 8.1 on number line

To find :  How to draw / locate

Solution:

Draw a number line  .

Mark a  point  A on - 8.1  on number line

& mark a point B on 1 on number line

Draw  perpendicular bisector of A & B which cuts number line at M

Draw a semi circle taking M as center & MA = MB radius

Draw  a perpendicular at MO   ( O being 0 )

which intersect  drawn semicircle at C

Taking O as center & compass width = OC , draw an  arc on right side of Zero

intersecting number line at P

P is  √8.1  on number  Line

Verification

AB = 8.1 + 1 = 9.1

Radius = MA =  MB = MC  = 9.1/2

OM  =   MB  - OB  = 9.1/2  - 1  

OC² =  MC² - MO²

=> OC² = (9.1/2)² - ( 9.1/2  - 1  )²

Using a² - b² = (a + b )(a - b)

=>  OC² = (8.1) (1)

=> OC = √8.1

Learn more:

Show root 7 on the number line - Brainly.in

https://brainly.in/question/4539966

Represent root 6.8 on a number line - Brainly.in

https://brainly.in/question/10304742

Similar questions