represent in polar form
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Hey, mate here is ur Ans
Multiplying nr and dn by 1-2i
(1-3i)(1-2i)/5
1-5i-6/5
-5-5i/5
-(1+i)
put 1=rcos@. and. 1=rsin@
squaring and adding we get
√2=r. and @=45
so, it's polar form is
-{√2cos(45)+√2isin45}
Multiplying nr and dn by 1-2i
(1-3i)(1-2i)/5
1-5i-6/5
-5-5i/5
-(1+i)
put 1=rcos@. and. 1=rsin@
squaring and adding we get
√2=r. and @=45
so, it's polar form is
-{√2cos(45)+√2isin45}
kunalkumar101:
-1-i
convert to polar form
good try but ans is wrong
@=a-π 3rd quad. @=(π/4)-π=(-3 π/4)
Answered by
0
Answer:
Polar form is that it is not completely donate it's electro for ex HCl
Step-byp explanation:
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