Question

Represent in the form of quadratic equation (x – 5) (x + 4) = (x + 1) (x + 2) – 2x 2 .

Answer 1

(x-5)(x+4) = (x+1)(x+2) - 2x²

(x)²+[(-5)(4)]x+(-5)(4) = (x)²+[(1)(2)]x+(1)(2) - 2x²

(by identity 4)

x²-20x-20 = x²+2x+2-2x²

(x²-20x-20)-(x²+2x+2-2x²) = 0

x²-20x-20-x²-2x-2+2x² = 0

x²-x²-2x²-20x-2x-20-2 = 0

-2x²-22x-22 = 0

-2(x²+11x+11) = 0

(dividing equation by -2)

x²+11x+11 = 0/-2

x²+11x+11 = 0

hope it helps you✌️