Represent in the polar form (a+ib)=(1+√3i)
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1
Answer:
Let z=−1−
3
i
Since −1−
3
i lies in third quadrant.
∴ Principal value of argz=−π+tan
−1
∣
∣
∣
∣
∣
∣
−1
−
3
∣
∣
∣
∣
∣
∣
−π+tan
−1
3
=−π+
3
π
=
3
−3π+π
=
3
−2π
and ∣z∣=
(−1)
2
+(−
3
)
2
=
1+3
=2
∴ Polar form of z=∣z∣[cos(argz)+isin(argz)]
Polar form of z=2[cos(
3
−2π
)+isin(
3
−2π
)]
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