Question

Represent irrational number √2 on the number line​

Answer 1

Step-by-step explanation:

Step I: Draw a number line and mark the centre point as zero.

Step II: Mark right side of the zero as (1) and the left side as (-1).

Step III: We won’t be considering (-1) for our purpose.

Step IV: With same length as between 0 and 1, draw a line perpendicular to point (1), such that new line has a length of 1 unit

Step V: Now join the point (0) and the end of new line of unity length.

Step VI: A right angled triangle is constructed.

Step VII: Now let us name the trianlge as ABC such that AB is the height (perpendicular), BC is the base of triangle and AC is the hypotenuese of the right angled triangle ABC.

Step VIII: Now length of hypotenuse, i.e., AC can be found by applying pythagoras theorem to the triangle ABC.

${ac}^{2} = {ab}^{2} + {bc}^{2} \\ = > {ac}^{2} = {1}^{2} + {1}^{2} \\ = > {ac}^{2} = 2 \\ = > ac = \sqrt{2}$

Step IX: Now with AC as radius and C as the centre cut an arc on the same number line and name the point as D.

Step X: Since AC is the radius of the arc and hence, CD will also be the radius of the arc whose length is 2–√2.

Step XI: Hence, D is the representation of 2–√2 on the number line.

Answer 2

Step-by-step explanation:

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