Represent Lewis structure of SO3 and assign the formal charge on each atom.
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Formal charge = valence electron – non bonding valence electron – bonding electron/2
Now, first we will find formal charge of sulfur (S)
S = 6 – 0 – 12/2 = 0
(S) = 0
So, the formal charge of sulfur is 0.
Now, we will find oxygen (O)
O = 6 – 4 – 4/2 = 0
(O) = 0
So, the formal charge of Oxygen is 0.
So, the entire so3 molecules has zero formal charge.
therefore, we can say that the overall formal charge of so3 molecules are zero.
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