Question

Represent of situation in the form of quadratic equation.
The area of rectangular plot is 528 m' The length of the plot (in metres) is one more than twice its breadth.
We need to find the length and breadth of plot.
मिति को द्विघात समीकरण को रूप में दर्शदए। आयताकार क्षेत्र का मेवाल 526 M है। क्षेत्र की लम्बाई चौड़ाई के दुगने से एक
मोटर अमिका है। हर्मोन की लम्बाई और वीाई मात करनी है।
a)2x-x+528-0 b) 2x +4-528 - 0 -2x1x-528 - 0 d)-28-1-528-0​

Answer 1

Step-by-step explanation:

let breatdh be X m

then , length = 2X+1 m

area = legth×breadth

528= x(2x+1)

2x^2 + x - 528 = 0

2x^2 - 32x + 33x - 528 = 0

2x(x-16) + 33(x+16) = 0

(2x +33)(x-16) = 0

therefore x = 16 or -33

as length cannot be negative

breadth = Xm = 16m

length = 2X + 1 m = 33m

Answer 2

Hey Mate Here is your Ans

Given

Area of rec plot = 528

from situation

Area of rec = Length x Breadth

so,put Area

528 = x multiply x......means Let L= x and B= x

As given l is 1 more than twice its breadth so,

L = 1 + 2 (B)....put it

528= x mul 2(X)

solve it

5 2 8 = 2xSquare +1

2 x squ +1 -528...

This is your quadratic equation......