Represent root 10 and 3 on a no line
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Answer:
here is your answer with diagrams
Answer:
To represent the √10 on the line first draw the right angle triangle in the xy-plane such that base on the x-axis and one end of triangle in on origin of plane and perpendicular is not on y-axis
lengths of sides are following
Base = b = 3
perpendicular = p = 1
Then by pathegorus theorem
h² = p² + b² = 3² + 1² = 9 + 1 = 10
h² = 10
h = √10
Now with the help of compass draw the arc of √10 on the line as shown in the first figure.
To represent the √3 on the line first draw the right angle triangle in the xy-plane such that base on the x-axis and one end of triangle in on origin of plane and perpendicular is not on y-axis
lengths of sides are following
Base = b = √2
perpendicular = p = 1
Then by pathegorus theorem
h² = p² + b² = √2² + 1² = 2 + 1 = 3
h² = 3
h = √3
Now with the help of compass draw the arc of length √3 on the line as shown in the second figure.
Note: In the second figure we draw first another triangle of base and perpendicular of size 1 units to find the √2 on the line then use that √2 as the base for required construction of √3