Question

represent root 3.5, root 9.4and root 10.5 on real number line
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Answer 1

Answer:

Represent √3.5 on number line Step 1: Draw a line segment AB = 3.5 units Step 2: Produce B till point C, such that BC = 1 unit Step 3: Find the mid-point of AC, say O. Step 4: Taking O as the centre draw a semi circle, passing through A and C. Step 5: Draw a line passing through B perpendicular to OB, and cut semicircle at D. Step 6: Consider B as a centre and BD as radius draw an arc cutting OC produced at E. In right ΔOBD, BD2 = OD2 – OB2 = OC2 – (OC – BC)2 (As, OD = OC) BD2 = 2 OC x BC – (BC)2 = 2 x 2.25 x 1 – 1 = 3.5 => BD = √3.5 Represent √9.4 on number line Step 1: Draw a line segment AB = 9.4 units Follow step 2 to Step 6 mentioned above. BD2 = 2OC x BC – (BC)2 = 2 x 5.2 x 1 – 1 = 9.4 => BD = √9.4 Represent √10.5 on number line Step 1: Draw a line segment AB = 10.5 units Follow step 2 to Step 6 mentioned above, we get BD2 = 2OC x BC – (BC)2 = 2 x 5.75 x 1 – 1 = 10.5 => BD = √10.5/represent-3-5-9-4-10-5-on-the-real-number-line

Step-by-step explanation:

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