represent root 5.7 on number line
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Heya!!! ✌️✌️
______________^_^
Here is your answer dear.....
Let K = 5.7 cm
Draw a right angle triangle with base of length (K-1)cm and hypotenuse (K+1)cm . The third side of the triangle represents twice the square root of K . i.e. 2√k . Thus we can bisect the line obtained to get √k
Explanation :-
This can be proved by Pythagoras theorem .
Length of third side = √{(K+1)^2-(K-1)^2} =2√K
The triangle can be constructed as explained :-
Draw the base line of length (K-1) cm .
Draw perpendicular line from one end of the base .
Cut an arc of length (K+1) cm from the other end of the base line to the perpendicular drawn.
Joint the point obtained to complete the triangle .
I HOPE THIS WILL HELP YOU OUT....
HAVE A GREAT DAY DEAR....
#Bhavana ☺️
______________^_^
Here is your answer dear.....
Let K = 5.7 cm
Draw a right angle triangle with base of length (K-1)cm and hypotenuse (K+1)cm . The third side of the triangle represents twice the square root of K . i.e. 2√k . Thus we can bisect the line obtained to get √k
Explanation :-
This can be proved by Pythagoras theorem .
Length of third side = √{(K+1)^2-(K-1)^2} =2√K
The triangle can be constructed as explained :-
Draw the base line of length (K-1) cm .
Draw perpendicular line from one end of the base .
Cut an arc of length (K+1) cm from the other end of the base line to the perpendicular drawn.
Joint the point obtained to complete the triangle .
I HOPE THIS WILL HELP YOU OUT....
HAVE A GREAT DAY DEAR....
#Bhavana ☺️
lucky477:
same to u and many many thanks
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