Question

represent root 5 on the number line

Answer 1

We draw a number line and mark the integers −2, −1, 0, 1, 2, 3, 4, etc. on it, so that the distance between any two consecutive integers is one unit. On this number line, we mark O and A at the points 0 and 2 respectively. At A, we draw AB of unit length which is perpendicular to OA. Now, we join OB. Taking O as the centre and OB as the radius, we will draw an arc which cuts the number line at P.

Now, point P represents the irrational numberon the number line. Let us verify it.
Using Pythagoras theorem in ΔOAB,
OB2 = OA2 + AB2
= 22 + 12
= 4 + 1
= 5

But OP = OB


Answer 2

here are steps

step1- draw number line

step2- mark a point a as -5 on the number line

step3- mark a point cas 1 on number line

step4- mark a point b as the mid -point of ac

step5- with point b as the centre and radius  as ab draw a semicircle

step6- from o draw a perpendicular line to the number line that intersects the previous drawn semi-circle at d here od square root of 5

step7- with o as centre and radius as od , drawn an arc that intersects the number line at the point E.Here E is the point square root of 5 .

hope i help u

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