represent root 6 and root 7 on the number line
Answers
√6 is less than 3 and more than 2 so it will come somewhere in middle of 2 and 3 and √ 7 will come just after √6
Answer:
have to construct √6 on the number line.
Steps:
1. Draw a horizontal line.
2. Now take a point A on the line and mark at pint B so that AB = 6 unit
3. From the point B, mark C such that BC = 1
4. Now take a point O in between A and B such that OA = OC = (6 + 1)/2 = 7/3 = 3.5 unit
5. Now draw a circle having center at O and radius 3.5 units.
6. Draw a perpendicular to AC passing through B and intersecting the semicircle at D.
7. With B as center and BD as redius, draw a circle such that it meets the number line at E.
Now, BE represents √6 on the number line which shown in the given figure.
how to construct √7 on number line.
1. Draw a number line
2. Mark 0,1,2,3,4,5,6,7 and so on
3. Mark Point A on 0 and B on 7
4. Mark a Point C on AB Produced Such That AB BC= 1unit
5. Find Mid Point Of AC and Name It O
6. Taking O as Centre Draw A Semi Circle
7. Draw A Perpendicular on B (7th unit) A nd Join With Semi Circle And Name It D
9. Taking B as Centre ,BD As Radius Draw OC Arc Cutting oc Produced OC ProducedE on Obtained Represents Root of 7
how to construct √8 on number line.
(see the image)
Hope it helps you....
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