represent root 8.5 on the number line
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Steps
1) Draw a line 8.5 units, mark A as 8.5 and B as 0.
2) Extend the line segment AB 1 unit and name it as C.
3) Construct perpendicular bisector of AC and mark point of intersection as O.
4) With O as center, and OA as radius, complete the semi-circle.
5) From the point B, construct a perpendicular, intersecting the semi-circle at D.
6) Then, BD = root 8.5.
7) With B as center and BD as radius, draw an arc, intersecting the line at E.
8) E is a point root 8.5.
Proof :-
AB = 8.5 units
AC = 9.5 units
OA = OC = 9.5/2, OD = 9.5/2
BC = 1 units
OC = 9.5/2 units
OB = OC - BC = 9.5/2 - 1
Therefore, OD² = OB² + BD² (Pythagoras Theorem)
So, BD = root 8.5.
plz mark as brainliest
1) Draw a line 8.5 units, mark A as 8.5 and B as 0.
2) Extend the line segment AB 1 unit and name it as C.
3) Construct perpendicular bisector of AC and mark point of intersection as O.
4) With O as center, and OA as radius, complete the semi-circle.
5) From the point B, construct a perpendicular, intersecting the semi-circle at D.
6) Then, BD = root 8.5.
7) With B as center and BD as radius, draw an arc, intersecting the line at E.
8) E is a point root 8.5.
Proof :-
AB = 8.5 units
AC = 9.5 units
OA = OC = 9.5/2, OD = 9.5/2
BC = 1 units
OC = 9.5/2 units
OB = OC - BC = 9.5/2 - 1
Therefore, OD² = OB² + BD² (Pythagoras Theorem)
So, BD = root 8.5.
plz mark as brainliest
ritika199:
u have just copied it..
i know..
but then also thnku for helping..
so ritika which class do you study in
Plz mark as brainliest
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