represent schematically the oxidation of glucose to get energy in our
1) body cells under normal condtions
2) muscles cells during strenuous exersice
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Answered by
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Explanation:
body cells under normal conditions
Answered by
4
Information about oxidation of glucose is written below-
Under normal conditions, body metabolizes glucose aerobically. It produces pyruvate from glucose in cytosol.
C6H12O6 --> CH3COCOO-
C6H12O6 represents glucose.
CH3COCOO-
C6H12O6 represents pyruvate.
Under strenuous exercise, glucose is metabolized into lactic acid due to lack of oxygen. This phenomenon usually occurs in muscles.
C6H12O6 --> CH3COCOO-
--NAD+--> C3H6O3
In this reaction, NADH is reduced to NAD+.
C3H6O3 is lactic acid.
Lactic acid production causes fatigue during strenuous exercise. It is further metabolized in presence of excess oxygen when you stop exercising.
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