Biology, asked by thaanisis12, 11 months ago

represent schematically the oxidation of glucose to get energy in our
1) body cells under normal condtions
2) muscles cells during strenuous exersice

Answers

Answered by radha151186
5

Explanation:

body cells under normal conditions

Answered by Anonymous
4

Information about oxidation of glucose is written below-

Under normal conditions, body metabolizes glucose aerobically. It produces pyruvate from glucose in cytosol.

C6H12O6 --> CH3COCOO-

C6H12O6 represents glucose.

CH3COCOO-

C6H12O6 represents pyruvate.

Under strenuous exercise, glucose is metabolized into lactic acid due to lack of oxygen. This phenomenon usually occurs in muscles.

C6H12O6 --> CH3COCOO-

--NAD+--> C3H6O3

In this reaction, NADH is reduced to NAD+.

C3H6O3 is lactic acid.

Lactic acid production causes fatigue during strenuous exercise. It is further metabolized in presence of excess oxygen when you stop exercising.

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