represent the Boolean expression P + Q R with the help of an nand Gate only
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Explanation:
Correct option is
D
OR gate
Given that
P+
P
ˉ
Q where P and Q are the inputs of the logic circuit,
Let Y=P+
P
ˉ
Q
=P(1)+
P
ˉ
Q
=P(1+Q)+
P
ˉ
Q ∵1+X=1
=P+PQ+
P
ˉ
Q
=P+Q(P+
P
ˉ
) ∵
X
ˉ
+X=1
=P+Q
Hence the following expression represents OR gate
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