Question

represent the cell from the following given reaction cl2+2ag gives to (2ag+)+ (2cl-)​

Answer 1

Answer:

The cell representation for the given cell reaction is,

$Ag\ /\ Ag^+\ //\ Cl^2^+\ /\ Cl^-$

Explanation:

The overall cell reaction is given as,

$Cl^{2+}\ +\ 2\ Ag\ --->\ 2\ Ag^{+}\ +\ 2\ Cl^{-}$

Here,

The oxidation state of the silver changes from $0$ to $+1$ oxidation state· This means that the silver gets oxidized to $Ag^+$ by losing $2$ electrons· Normally, the oxidation will take place at the anode in an electrolytic cell·

Therefore, the oxidation half cell reaction that occurs at the anode is,

     $2\ Ag\ --->\ 2\ Ag^+\ +\ 2e^-$

The chloride ion is reduced from its $+2$ oxidation state to $-1$ oxidation state by gaining  $2$ electrons· Normally, the reduction will take place at the cathode in an electrolytic cell·

Therefore, the reduction half cell reaction that occurs at the cathode is,

      $Cl^{2+}\ +\ 2e^-\ --->\ 2\ Cl^-$

By adding these two half cell reactions, we get the overall cell reaction·

For the cell representation,

• The anode half cell and the cathode half cell is separated by two vertical lines which indicate the salt bridge that connects the two electrolytic solutions·
• Within the half cells at the anode and the cathode, the metal and its electrolyte solution is separated by a single vertical line·

• The anode half cell is represented first, on the left-hand side and then represents the cathode half cell, on the right-hand side·

Therefore, the cell representation for the given cell reaction is,

    $Ag\ /\ Ag^+\ //\ Cl^2^+\ /\ Cl^-$