Represent the following situations in the form of quadratic equation: (a) The area of a rectangular plot is 465 m^2. The length of the plot is one more than twice its breadth. We find find to the length and breadth of the plot?
Answers
Let the breadth of the rectangular plot = x m
Then, the length of the plot =(2x + 1) m.
Formula of area of rectangle = length × breadth
Area of rectangular plot =528 m² (given)
Putting the value of length and width, we get
⇒(2 x + 1) × x = 528
⇒ 2 x² + x =528
⇒ 2 x² + x – 528 = 0
Since ,it is of the form ax² + bx+c=0, where a≠0.
Thus it represents the required quadratic equation.
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(ii)
Let the first integer = x
Next consecutive positive integer will = x + 1
A.T.Q
Product of two consecutive integers = 306 (given)
⇒x × (x +1) = 306
⇒ x² + x = 306
⇒ x²+ x – 306 = 0
Since ,it is of the form ax² + bx+c=0, where a≠0.
Thus it represents the required quadratic equation.
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(iii)
Let the Rohan’s age = x years
Then, his mother’s age = (x + 26)yr
After 3 years from now
Rohan’s age = (x + 3)yr
Rohan’s mother's age will = (x + 26 + 3 ) = (x + 29)yr
A.T.Q
The product of their ages 3 years from now will be 360 so that
(x + 3)(x + 29) = 360
⇒ x² + 29 x + 3 x + 87 = 360
⇒ x² + 32 x + 87 – 360 = 0
⇒ x² + 32 x – 273 = 0
Since ,it is of the form ax² + bx+c=0, where a≠0.
Thus it represents the required quadratic equation.
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(iv)
1st case:
Let the speed of train be x km/h.
Distance travelled by the train= 480 km
Time taken to travel 480 km = 480/x h ( time= distance/speed)
2nd case:
Let the speed of train = (x – 8) km/h
Distance is same in both the cases
Time taken to travel 480 km = (480/x -8) h
A.T.Q
(480/ X-8 ) =3 + (480 /X)
(480/ X-8 ) - (480 /X) =3
(480X- 480(X-8)) /X(X-8) =3
480 X- 480 X+3840 = 3 X(X-8)
⇒3840 = 3 X² -24 X
⇒3 X² -24 X - 3840 = 0
⇒3 ( X² -8X -1280) =0
⇒X² -8 X -1280=0
Since ,it is of the form ax² + bx+c=0, where a≠0.
Thus it represents the required quadratic equation.
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(i)
Let the breadth of the rectangular plot = x m
Hence, the length of the plot is (2x + 1) m.
Formula of area of rectangle = length × breadth = 528 m2
Putting the value of length and width, we get
(2x + 1) × x = 528
⇒ 2x2 + x =528
⇒ 2x2 + x - 528 = 0
(ii)
Let the first integer number = x
Next consecutive positive integer will = x + 1
Product of both integers = x × (x +1) = 306
⇒ x2 + x = 306
⇒ x2 + x - 306 = 0
(iii)
Let take Rohan's age = x years
Hence, his mother's age = x + 26
3 years from now
Rohan's age = x + 3
Age of Rohan's mother will = x + 26 + 3 = x + 29
The product of their ages 3 years from now will be 360 so that
(x + 3)(x + 29) = 360
⇒ x2 + 29x + 3x + 87 = 360
⇒ x2 + 32x + 87 - 360 = 0
⇒ x2 + 32x - 273 = 0
(iv)
Let the speed of train be x km/h.
Time taken to travel 480 km = 480/x km/h
In second condition, let the speed of train = (x - 8)
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