Question

Represent the following situations in the form of quadratic equations :
1) The area of a rectangular plot is 528 m². The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.​

Answer 1

Answer:

2x^²+x-520=0

Step-by-step explanation:

let b=x

::l=2x+1

area of rectangle=l*b

x*(2x+1)=520

::2x^²+x=520✓✓✓✓✓

hopefull answer

Answer 2

★ Given :-

• The area of a rectangular plot is 528 m².
• The length of the plot (in metres) is one more than twice its breadth.

★ Have to Find :-

• Find the length and breadth of the plot.

★ Solution :-

Let us we consider the breadth of the rectangular plot be " x " metres.

Then, from given we know

The length of the plot (in metres) is one more than twice its breadth.

So, According to this ,

↬ Length of the rectangular plot be (2x + 1)

As we all know the formula of area of rectangle.

The plot is in rectangular shape.

So,

Area of rectangular plot = l × b

We know ,

➤ l = ( 2x + 1 )

➤ b = x

Therefore , forming the equation :-

↬ ( 2x + 1 ) * x = 528

↬ 2x² + x - 528 = 0

By using the Splitting the middle term method :-

↬ 2x² + 33x - 32x - 528 = 0

↬ x( 2x + 33 ) - 16( 2x + 33 ) = 0

↬ 2x + 33 = 0 ; x - 16 = 0

↬ x = - 33/2 and x = 16

Now,

Breadth of rectangular plot = x = 16m

Length of rectangular plot = ( 2x + 1 )

↬ 2(16) + 1 = 33 m

Therefore,

Length of plot ↬ 33 m$.$

Breadth of plot ↬ 16 m.

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