Question

Represent the points M(3, 4), N(-3, -2), P(-2, 5) and Q(4, -1) on the graph paper. Draw line MN and line PQ. From the graph find their point of intersection.

Answer 1

Answer:

It is given

3x−2y=4

We can also write it as

2y=3x−4

y=

2

3x−4

Substituting x=2 in the given equation

y=

2

3(2)−4

So we get

y=

2

6−4

y=

2

2

By division

y=1

Substituting x=−2 in the given equation

y=

2

3(−2)−4

So we get

y=

2

−6−4

y=

2

−10

By division

y=−5

x 2 -2

y 1 -5

Now draw a graph using the points A(2,1) and B(-2,-5)

Join the points AB through a line and extend in both the directions

It is given

x+y−3=0

We can also write it as

y=3−x

Substituting x=1 in the given equation

y=3−1 So we get

y=2

Substituting x=−1 in the given equation

y=3−(−1)

So we get

y=4

x 1 -1

y 2 4

Now draw a graph using the points C(1,2) and D(−1,4)

Join the points CD through a line and extend in both the directions.

Therefore the coordinates of the point where the two graph lines intersect is A(2,1)

Answer 2

Step-by-step explanation:

Hope it is helpful to you.