represent the zeros of p(x)=x2-4x+3 by the graph
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2
can't do graph here, yaar
sannu9:
yaaa
Answered by
3
x2-4x+3
x2-3x-x+3
x(x-3)-1(x-3)
(x-1)(x-3)
x=1,3
x2-3x-x+3
x(x-3)-1(x-3)
(x-1)(x-3)
x=1,3
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