Question

Represent z=1+i in polar form

Answer 1

Answer:

$z = \sqrt{a {}^{2} } + b ^{2} \\ z = \sqrt{2 } \\ polar \: form \: \\ r{ \sin( + \sec( \\ \\ ) )$

Step-by-step explanation:

sorry as I am first time using calculator of this aap so sorry

Answer 2

Answer:

hello

Step-by-step explanation:

$z = 1 + i = \sqrt{2} ( \frac{1}{ \sqrt{2} } + i \frac{1}{ \sqrt{2} } ) - - - (i)$

let polar form of given equation be z= r cos(a)+ ir sin(a) --------------(2)

Comparing (1) and (2)

we can write,

r cos (a)=

$\sqrt{2} \times \frac{1}{ \sqrt{2} } = \sqrt{2} \cos(45)$

r sin (a)=

$\sqrt{2} \times \frac{1}{ \sqrt{2} } = \sqrt{2} \sin(45)$

$z = \sqrt{2} ( \cos(45) + i \sin(45)$

ok marks the brainlist❤☺