Question

Required
7. A box contains 6 pink, 4 red and
5 yellow marbles. If 2 marbles are
picked at random, then find the
probability that the marbles are
either yellow or pink?
9/31
15/29
11/34
5/21​

Answer 1

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Given that there are 6 pink marbles, 4 red marbles, 5 yellow marbles

The total marbles are = 15

The Probability of either yellow and pink is 

=⁵C2+⁶C2

The probability is 

= ( ⁵C2+⁶C2 ) / ¹⁵C2

=((5×4)+(6×5))/(15×14)

=(20+30)/(210)

=50/210

=25/105

=5/21

Hence the output will be 5/21

Answer 2

Answer:

The probability that both marbles are either yellow or pink is equal to 5/21.

Therefore, option (4) is correct.

Step-by-step explanation:

Given, the number of pink marbles = 6

The number of red marbles = 4

The number of yellow marbles = 5

Total number of marbles in the box =  6 + 4 + 5 = 15

If one marble is picked out then it can not be replaced, it means for next turn there will be one marble less in the box.

To calculate the probability of that the marbles are either yellow or pink -

Probability  $=\frac{5}{15} \times \frac{4}{14} +\frac{6}{15} \times \frac{5}{14}$

                  $=\frac{20}{210} +\frac{30}{210}$

                  $=\frac{50}{210}$

                  $=\frac{5}{21}$

Therefore, the probability that the marbles are either yellow or pink is 5/21.

To practice more :-

https://brainly.in/question/4889631          

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