Question

Required Output: 16

#include<stdio.h>
int main()
{
int count = 80;
int ij,k=9;
for(i = 1, j=1;i<k &&j<k; j++)
{
if (___________)
{
j=0;
i++;
}
count = count - 1;
}
printf("%d",count);
return 0;
}​

Answer 1

Answer:

j==8

Explanation:

when ever j becomes 8 it becomes zero again and i value increments by 1 till 8 so 8*8=64

80-64=16

So Answer is j==8