Question

required volumes of water to dissolve 1 g baso4 ksp=1.1 × 10^-10​

Answer 1

Answer:

408.7 liters

Explanation:

Answer 2

Let S moles/L of BaSO4 be soluble in water
Therefore, Ksp=S^2
=>1.1*10^(-10)=S^2
=>S=((1.1)^(0.5))*10^(-5)= 1.05*10^(-5) approx.
Therefore, 1.05*10^(-5) moles of BaSO4 must dissolve in 1L of water
Therefore, 233*1.05*10^(-5) g of BaSO4 must dissolve in 1L of water
Therefore, 1g of BaSO4 must dissolve in (10^5)/(233*1.05) L of water=408.7 L