Question

res 50. If the weight of metal oxide is x g containing y g of oxygen, the equivalent weight of metal will be es 8(y - x) 8x (1) E= у (2) E= Х n (3) E= y 8 8(x - y) y 100 (4) E=​

Answer 1

Answer:

8(x/y-1)

Explanation:

One equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8g of oxygen atoms. Therefore, equivalent weight of metal is 8(x/y-1).