Question

res - The sum of three consecutive odd numbers is 33. The sum of two numbers is 87. If twice the smaller number is added to the larger number, the Find the larger number, a consecutive numbers such that the sum of the first and second is 15 more than th​

Answer 1

Answer:

Let

x= smallest odd number in our problem

Consecutive odd numbers would be x,x+2,x+4

The sum of these consecutive odd numbers is 33

(x)+(x+2)+(x+4)=33

Opening brackets

3x+6=33

Subtracting 6 on both sides

3x=27

Dividing by 3 on both side

x=9

Hence, the smallest odd number whose sum with two successive odd numbers would give a total of 33 is 9.

Answer 2

Answer:

$\qquad\qquad\underline{\textsf{\textbf{ \color{magenta}{AnSwEr} }}}$

Let the numbers be a, a + 2 and a + 4

According to question,

a + a + 2 + a + 4 = 33

=> 3a + 6 = 33

=> 3a = 27

=> a = 9

First number = 9

Second number = 9 + 2 = 11

Third number = 9 + 4 = 13