English, asked by sharanyaa60, 5 months ago

Research on both a folk singer and folk musician of Arunachal Pradesh/Meghalaya.
Folk Singer: His life, his composition in the native language, translation of the composition in English, Explanation of its theme genre and the message being conveyed, poetic devices used, pictures, etc.
when was it sung
Folk Musician: Any musician who plays any native musical instrument with its type, description of the musician and the instrument, its significance in the music world, any composition by that musician on that instrument, its meaning, rythm composed, origin, characteristics, nature, development from past till now in modern times, its position in India and the world, number of people indulged, scope in future, etc

Answers

Answered by taqueerizwan2006
0

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Time=10\:sec\:and\:30\:sec}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline{\bold{Given :}}}  \\  \tt:  \implies Velocity \: of \: boy = 50 \: m/s \\  \\  \tt:  \implies Velocity \: of \: girl = 30 \: m/s \\  \\  \tt:  \implies Acceleration \: of \: boy =  {1 \: m/s}^{2}  \\  \\ \tt:  \implies Acceleration \: of \:girl=  {2\: m/s}^{2}  \\  \\  \tt:  \implies Sepration \: between \: them = 150 \: m \\  \\ \red{\underline{\bold{To \: Find :}}} \\  \tt:  \implies Time \: taken \: to \: catch \: the \: girl =?

• According to given question :

 \green{\star} \:  \text{Using \: relative \: motion \: method} \\  \\  \green{ \circ} \:  \tt Net \: velocity = 50 - 30 = 20 \: m/s \\  \\ \green{ \circ} \:  \tt Net \: acceleration = 1 - 2 = - 1\: m /{s}^{2}  \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies s = ut +  \frac{1}{2}  {at}^{2}  \\  \\ \tt:  \implies 150 = 20 \times t +  \frac{1}{2}  \times  -1 \times  {t}^{2}  \\  \\ \tt:  \implies 300 = 40t -  {t}^{2}  \\  \\ \tt:  \implies  {t}^{2}  - 40t  + 300 = 0 \\  \\ \tt:  \implies t =  \frac{  - ( - 40) \pm\sqrt{ { (- 40)}^{2}  - 4 \times 1 \times 300} }{2 \times 1}  \\  \\ \tt:  \implies t =  \frac{40 \pm \sqrt{1600 - 1200} }{2}  \\  \\ \tt:  \implies t =  \frac{40 \pm 20}{2}  \\  \\  \green{\tt:  \implies t = 10 \: sec \: and \: 30 \: sec}

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