Question

reset answer
5 A body of 2.5-kg mass in moving with a constant velocity of 5 m/s. In order to bring it to rest at a distance of 4m, the force required is
s: A
7.8125 N
B.
0 11.4150 N
C.
4.6375 N
D. O 2.25 N​

Answer 1

Answer:

Given:- m= 2.5kg

u=5m/s

v=0m/s

s=4m

As per relation,

v²-u²=2as

0²-5²=2×a×4 =>a = 3.125m/s²

Now,

F=ma

=>F=2.5×3.125N

=>F = 7.8125N