Question

reshma is fly fishing in a stream the tip of her fishing is 1.8m above the surface of the water and the fly at the end of the string rests on the water 3.6m away and 2.4m form point directly under the tip of the rod​

Answer 1

Step-by-step explanation:

Given reshma is fly fishing in a stream the tip of her fishing is 1.8 m above the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from point directly under the tip of the rod. Assuming that her string (from the tip of her rod to the fly) is taut, how much string does she have out if she pulls in the string at the rate of 5 cm per second, what will be the horizontal distance of the fly from her after 12 seconds?

• So we need to draw a right angle triangle ABC in which the distance of the perpendicular AB is 1.8 m and base BC is 2.4 m  
• We need to find the length of AC
• So AC^2 = AB^2 + BC^2
• So AC = √AB^2 + BC^2
• So AC = √(1.8)^2 + (2.4)^2
•            = √3.24 + 5.76
•           = √9
•            = 3 m
• So she pulls the string at the rate of 5 cm / sec
• So length of string pulled in 12 secs will be 12 x 5 = 60 cm
•                                                                                 = 0.6 m
• So remaining length of string will be 3 – 0.6 = 2.4 m
• Now a right angle triangle ABD is formed with hypotenuse 2.4 m, height AB = 1.8 m and we need to find the length of BD.
• So BD^2 = AD^2 – AB^2
• So BD = √(2.4)^2 – (1.8)^2
•            = √5.76 – 3.24
•          = √2.52
•   BD = 1.58 m
• So horizontal distance of the fly after 12 secs will be                          1.2 + 1.58 = 2.78 m

Reference link will be

https://brainly.in/question/8120994