Question

resistance between a and b.
with full solution...

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beizzat ho jao gai...​

Answer 1

Answer:

Here in th extreme left the two 3 ohm resistors are in series so their equivalent resistance is = 6 ohm , which is in parallel with another 6 ohm resistor .

So their equivalent is = R1 = (6x6) / 12 = 3 ohm .

R1 is again in series with 3 ohm resistor and their equivalent is in parallel with the second 6 ohm resistor from the left .

So the equivalent resistance is , R2 = (6x6) / 12 = 3 ohm .

R2 is again in series with 3 ohm resistor and their equivalent is in parallel with the third 6 ohm resistor from the left .

So the equivalent resistance is , R3 = (6x6) / 12 = 3 ohm .

This R3 is in series with 3 ohm resistor in th extreme right and then their equivalent is in parallel with the 3 ohm resistor between A and B points.

So the equivalent resistance is , RAB = (6x3) / 9 = 2 ohm .

Hope this helps you.

Answer 2

Explanation:

AF and FE are in series so R=3+3=6 ohm

Now eq of AF and FE is in parallel with AE so

1/R=1/6+1/6=3 ohm

now this equivalent is in series with ED so

3+3= 6 ohm

now it is in parallel with AD

1/R=1/6+1/6=3 ohm

now it is in series with DC

3+3 = 6 ohm

parallel with AC

1/R=1/6+1/6= 3

series with CB 3+3= 6 ohm

parallel with AB 1/6+1/3 = 2 ohm