Question

Resistance increases with decrease in cross sectional area. prove that .

Class 10th
Chapter - Electricity

Please be kind and help me

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Answer 1

the answer is ......

The longer the cylinder, the higher the resistance. Additionally, the resistance is inversely proportional to the cross sectional area A. If the diameter of the cylinder is doubled, the cross-sectional area increases by a factor ....

What happens to resistance when diameter increases?

Because the thickness of a wire is usually represented by its diameter. Thus when the diameter of a wire is doubled (made 2 times), its resistance becomes one-fourth (1/4), and if the diameter of a wire is halved (made 1/2), then its resistance becomes four times (4 times).....

refer the pic

hope thats the right one ... ..

Answer 2

$\huge {\boxed {\mathbb {QUESTION}}}$

Resistance increases with decrease in cross sectional area. prove that .

$\huge {\boxed {\mathbb {ANSWER}}}$

${\boxed {R=\rho \frac{l}{A}}}$

• $R=Resistance$
• $l=length$
• $A=Area\: of \:cross\: section$

$R \alpha\frac{l}{A}$

• $R \:is\: directly\: proportional\: to\: l$
• $R\: is \:inversely\: proportional\: to\: A$

$\therefore Resistance\: increases\: with\: decrease \:in \\cross \:sectional \:area.$

$\huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU }}}$

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$\huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$Formulas$

$I=\frac{Q}{t}$

$V=\frac{W}{Q}$

$V=IR$

$R=\rho \frac{l}{A}$

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