Question

Resistance of 0.1 m kcl solution in a conductance cell is 300 ohm and conductivity is 0.013 scm1. The value of cell constant is

Answer 1

Answer:

= 0.39 cm⁻¹

Explanation:

we know,

k=(1/R) × (l/A)

here, R= Resistance of the solution

         l = distance between two electrode

         A = Area

          k = Conductance

         C = concentration of the solution

cell constant = l/A

so, l/A= value of cell constant = k × R × C = 300 × 0.013 × 0.1 = 0.39 cm⁻¹