Question

Resistance of 0.2 M solution of an electrolyte is 50 W. The specific
conductance of the solution is 1.3 S m-1. If resistance of the 0.4 M solution
of the same electrolyte is 260 W, its molar conductivity is​

Answer 1

Answer:

We know,

R=

K

1

×

A

l

50=

1.4

1

×

A

l

A

l

=70m

−1

Again,

280=

K

1

×70

K=

4

1

Sm

−1

Now,

Λ

m

=

M

k×1000

×(10

−2

)

3

Λ

m

=

4

1

×(

M

1000

)(10

−2

m)

3

=

4

1

×

0.5

1000

×10

−6

=500×10

−6

=5×10

−4

Sm

2

mol

−1

Hence, option C is correct.