Resistance of 0.2 M solution of an
electrolyte is 50 W. The specific
conductance of the solution is 1.3 S
m-1. If resistance of the 0.4M
solution of the same electrolyte is 260
W, its molar conductivity is
Answers
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Explanation:
We know,
R=
K
1
×
A
l
50=
1.4
1
×
A
l
A
l
=70m
−1
Again,
280=
K
1
×70
K=
4
1
Sm
−1
Now,
Λ
m
=
M
k×1000
×(10
−2
)
3
Λ
m
=
4
1
×(
M
1000
)(10
−2
m)
3
=
4
1
×
0.5
1000
×10
−6
=500×10
−6
=5×10
−4
Sm
2
mol
−1
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