Question

resistance of 3 ohms is connected in parallel to a galvanometer resistance 297 ohms find the fraction of current passing through galvanometer

Answer 1

1/R = 1/R1 + 1/R2
1/R = 1/3 + 1/297
1/R= 99 + 1/297
1/R = 100/297
R = 2.97 ohm

Answer 2

Solution

resitance of galvanometer Rg= 297 ohm

restance which connect in parallel R1 = 3 ohm

let consider if the current flow in the ckt is= i

current which passing through the galvanometer is =Ig.

then

Ig=. (R1/R1+Rg)*i

Ig = (3/300)*i. R1+Rg= 300

Ig=0.01 i

Ig= 1% of i