Question

Resistance of a 0.1 M KCl solution in a conductance
cell is 200 ohm and conductivity is 0.015 S cm-?
The value of cell constant is
A
4.5 cm-1
B
3.0 cm-1
C
6.3 cm-1
5.2 cm-​

Answer 1

Answer: (B) 3.0 /cm¹

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Answer 2

Given:

Concentration of KCl solution, C = 0.1 M

Resistance, R = 200 Ω

Conductivity, κ = 0.015 S cm⁻¹

To Find:

The value of the cell constant of the given conductance cell.

Calculation:

- The cell constant is given by the formula:

Cell Constant = κ × R

⇒ Cell Constant = 0.015 × 200

⇒ Cell Constant = 3 cm⁻¹

- So the cell constant is 3 cm⁻¹.

- Hence, the correct answer is option (B) 3.0 cm⁻¹.