Resistance of a 10m long wire is 10 ohm by stretaching it 25%
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Step-by-step explanation:
1) On stretching the wire, it's length and Area of Cross section changes but Volume remains constant.
We know.
R = pl/A
R = pl * l /(A*l ) = pl^2/V
R α l^2
where
l. = length of wire
A = Area of cross section of wire.
V = Volume of wire.
2) After increasing the length of wire by 25%,then
Final length of wire, l(f) = 10 + 10 * (25/100)
= 10 + 2.5 = 12.5 m
We got that ,
R α l^2. -(1)
And
R(i) = 10ohm
R(f) = R
l(i) = 10m
l(f) = 12.5 ohm.
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