Math, asked by Sanskritigarg6994, 10 months ago

Resistance of a 10m long wire is 10 ohm by stretaching it 25%

Answers

Answered by Hanemanh
1

Step-by-step explanation:

1) On stretching the wire, it's length and Area of Cross section changes but Volume remains constant.

We know.

R = pl/A

R = pl * l /(A*l ) = pl^2/V

R α l^2

where

l. = length of wire

A = Area of cross section of wire.

V = Volume of wire.

2) After increasing the length of wire by 25%,then

Final length of wire, l(f) = 10 + 10 * (25/100)

= 10 + 2.5 = 12.5 m

We got that ,

R α l^2. -(1)

And

R(i) = 10ohm

R(f) = R

l(i) = 10m

l(f) = 12.5 ohm.

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